Engineer IDEA

103022 1439 28

6)Under Reinforced & Over Reinforced

Design Principles of Concrete Structures

Lecture 6

Under Reinforced & Over Reinforced

(Derivation)

Under-Reinforced Failure

Stage-I, Un-cracked Section

N.A. position is fixed, means “la” remains constant. Only “T” and “Cc” increase with the increase of load

Stage-II, Cracked Section

When section cracks, N.A. moves towards compression face means “la” increases. “T” and “Cc” also increase.

a/2 Cc

103022 1439 3

103022 1439 4

103022 1439 5

Internal Force Diagram

Under-Reinforced Failure (contd…)

Stage-III, Yielding in Steel Occur

T = As fy remains constant and Cc also remains constant. “la” increases as the

N.A. moves towards compression face because cracking continues.

Failure initiates by the yielding of steel but final failure is still by crushing of concret.

103022 1439 6

Und er-Reinforced Failure( contd…).

Derivation for p

Design Moment Capacity

For tension controlled sectio<D 0..9

And

103022 1439 7

UnderReinforced Failure (contd.,.. “‘ ,. )

Put value  of
  from (1to 
(2)

103022 1439 8 103022 1439 9

103022 1439 10

For econon1ical Design

103022 1439 11

103022 1439 12

By Simplifaication

103022 1439 13

103022 1439 14

103022 1439 16 103022 1439 17


103022 1439 18

As we know, Reinforcement Ratio is,


103022 1439 19

So,

Area of Steel Awill be

𝐴𝑠 = 𝜌 × 𝑏𝑑

Trial Method for the determination of “As

103022 1439 20

Trial # 1, Assume some value of “a” e.g. d/3 or d/4 or any other reasonable value, and put in (C) to get “As”

Trial # 2, Put the calculated value of “As” in

  1. to get “a”. Put this “a” value in (C) to get

    “As”

    Keep on doing the trials unless “As” from a specific trial becomes equal to the “As” calculated from previous trial.

    THIS VALUE OF AS WILL BE THE FINAL ANSWER.

    Is The Section is Under-Reinforced or NOT?

    1. Calculate ρ and if it is less than ρmax, section is under reinforced
    2. Using “a” and “d” calculate εt if it is ≥ 0.005, section is under-reinforced (tension controlled)
    3. If section is over-reinforced than in the following equation –ve term will appear in the under-root.

103022 1439 21

103022 1439 22Over-Reinforced Failure

Stage-I, Un-cracked Section

Stage-II, Cracked Section

These two stages are same as in under-reinforced section.

Stage-III, Concrete reaches strain of

0.003 but steel not yielding

We never prefer to design a beam as over- reinforced (compression controlled) as it will show sudden failure.

Φ = 0.65  εs < εy fs<fy

Stage-III, Concrete reaches strain of 0.0103 but steel not yielding (co11td )

103022 1439 23

103022 1439 24

103022 1439 25

StageIII, Concretreaches strain o0.003 busteel noyielding(contd…)

Putting value of  fs from (iv to (ii)

103022 1439 26

103022 1439 27

Summary

103022 1439 28

Concluded

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top